(21x^3-35x^2)/7x

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Solution for (21x^3-35x^2)/7x equation: 


x in (-oo:+oo)

x*((21*x^3-(35*x^2))/7) = 0

x*((21*x^3-35*x^2)/7) = 0

(x*(21*x^3-35*x^2))/7 = 0

21*x^3-35*x^2 = 0

7*x^2*(3*x-5) = 0

3*x-5 = 0 // + 5

3*x = 5 // : 3

x = 5/3

7*x^2*(x-5/3) = 0

(7*x*x^2*(x-5/3))/7 = 0

( 7*x^2 )

7*x^2 = 0 // : 7

x^2 = 0

x = 0

( x-5/3 )

x-5/3 = 0 // + 5/3

x = 5/3

( x )

x = 0

x in { 0, 5/3, 0 }

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